Answer:
16.93 m
Step-by-step explanation:
The triangle for the given scenario is shown below.
From the triangles [tex]\Delta ABC[/tex] and [tex]\Delta ABD[/tex],
AB is the pole height, BC or BD is the distance of either of the wire guys from the foot of pole, and [tex]\angle C[/tex] or [tex]\angle D[/tex] is the angle that each either of the guys make with the top of pole.
Let the distance of either of the wire guys from the foot of pole be [tex]x[/tex].
Now, consider [tex]\Delta ABC[/tex].
Given: AB = 9 m, BC = [tex]x[/tex], and [tex]\angle C=28[/tex]°.
Using tan ratio of the angle C, we get
[tex]\tan (\angle C)=\frac{AB}{BC}\\\tan (28)=\frac{9}{x}\\x=\frac{9}{\tan (28)}=16.93[/tex]
Therefore, 16.93 m away from the foot of the pole are the guys anchored.
