Answer:
24.3 m
Explanation:
Using the equation of motion
[tex]S=ut+0.5at^{2}[/tex] where s is the distance, u is initial velocity, t is time and a is acceleration
Substituting u for 6 m/s, t for 3 s, a for 1.4 m/s2 we obtain
[tex]S=6*3+(0.5*1.4*3^{2}=18+6.3=24.3 m [/tex]