17) mol of [tex]H_{2}O[/tex] = [tex] \frac{no. of molecule}{L} [/tex]
= [tex] \frac{1000 molecules}{6.03 * 10^{23} molecules/mol } [/tex]
= 1.658 * [tex]10^{-21} mol [/tex]
18) mol = [tex] \frac{molecule}{L} [/tex]
[tex] \frac{Mass}{Mr} = \frac{Molecule}{L} [/tex]
Let mass of oxygen = x
[tex] \frac{x}{(2 * 1) + (16)} = \frac{6 * 10^{23} }{6.03 * 10^{23} } [/tex]
[tex]x = (6 * 10^{23} ) (18 g/ mol)[/tex]
= 17.9 g
