The general form of the equation of a circle with radius ' r '
and centered at (a, b) is
(x - a)² + (y - b)² = r²
I'm pretty sure that your circle is not "at (-2,1)".
I'm going to approach your question assuming that
the circle's center is there.
Since the circle's center is at (-2, 1), the left side of its equation is
(x + 2)² + (y - 1)² = .
The distance from the center to (-4, 1) is the circle's radius.
That distance is 2, so the right side of the equation is
4 .
