Answer:
The Proof is given below.
Step-by-step explanation:
Given:
[tex]\overline{HF}[/tex] bisect ∠ EHG.i.e
∴ ∠EHF ≅ ∠ GHF
[tex]\overline{EH} \cong \overline{GH}[/tex]
To Prove:
[tex]\overline{EF} \cong \overline{GF}[/tex]
Proof:
In Δ EHF and Δ GHF
EH ≅ GH ………............{Given}
∠ EHF ≅ ∠ GHF …………..{EF bisect ∠ EHG as given above}
HF ≅ HF ………............{Reflexive Property}
Δ EHF ≅ Δ GHF …................{ By Side-Angle-Side test}
∴ EF ≅ GF........{corresponding parts of congruent triangles (c.p.c.t).}
[tex]\overline{EF} \cong \overline{GF}[/tex] ....... PROVED
