Answer:
The measure of the perpendicular KD is 8.72 unit .
Step-by-step explanation:
Given as :
The triangle AKM , with KD perpendicular to AM
The measure of side AK = 6 unit
The measure of side KM = 10 unit
The ∠ AKM = 93°
Let The measure of side KD = x unit
Now,
∵ KD ⊥ AM , KD divide the angle ∠ AKM equally
So, ∠ AKD = ∠ [tex]\dfrac{AKM}{2}[/tex]
I.e ∠ AKD = ∠ [tex]\{93}{2}[/tex]
∴ ∠ AKD = 46.5°
Now, Again
Cos Ф = [tex]\dfrac{AK}{KD}[/tex]
I.e Cos 46.5° = [tex]\dfrac{6}{KD}[/tex]
I.e 0.688 = [tex]\dfrac{6}{KD}[/tex]
∴ KD = [tex]\dfrac{6}{0.688}[/tex]
I.e KD = 8.72 unit
Hence The measure of the perpendicular KD is 8.72 unit Answer
