The mass of the water is 41.9 g
Explanation:
When an amount of energy Q is supplied to a sample of substance of mass m, the temperature of the substance increases by [tex]\Delta T[/tex], according to the equation :
[tex]Q=mC_s \Delta T[/tex]
where :
m is the mass of the substance
[tex]C_s[/tex] is the specific heat capacity of the substance
[tex]\Delta T[/tex] is the change in temperature
In this problem, we have:
Q = 525 J is the amount of heat supplied to the water
[tex]\Delta T = 3^{\circ}C[/tex] is the change in temperature of the water
[tex]C_s = 4.18 J/gC[/tex] is the specific heat capacity of the water
Solving for m, we find the mass of the water:
[tex]m=\frac{Q}{C_s \Delta T}=\frac{525}{(4.18)(3.0)}=41.9 g[/tex]
Learn more about specific heat capacity:
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