Answer:
178378378.37 Pa
0.01897
Explanation:
F = Force = [tex]6.6\times 10^4\ N[/tex]
A = Area = [tex]3.7\times 10^{-4}\ m^2[/tex]
Y = Young's modulus of bone under compression = [tex]9.4\times 10^{9}\ Pa[/tex]
[tex]\varepsilon[/tex] = Strain
Stress is given by
[tex]\sigma=\frac{F}{A}\\\Rightarrow \sigma=\frac{6.6\times 10^4}{3.7\times 10^{-4}}\\\Rightarrow \sigma=178378378.37\ Pa[/tex]
The maximum stress that this bone can withstand is 178378378.37 Pa
Compression force is given by
[tex]F=Y\varepsilon A\\\Rightarrow \varepsilon=\frac{F}{YA}\\\Rightarrow \varepsilon=\frac{6.6\times 10^4}{9.4\times 10^{9}\times 3.7\times 10^{-4}} \\\Rightarrow \varepsilon=0.01897[/tex]
The strain that exists under a maximum-stress condition is 0.01897
