Answer:
The rate of heat rejection will be 347 GJ/hr
Explanation:
We have given that power plant uses energy of 365 GJ/hr
So energy uses [tex]Q_B=365GJ/hr[/tex]
Work done from turbine [tex]W_T=18GJ/hr[/tex]
We have to find the rate of heat rejection to the atmosphere [tex]Q_C[/tex]
We know that [tex]Q_B=W_T+Q_C[/tex]
[tex]365=18+Q_C[/tex]
[tex]Q_C=347GJ/hr[/tex]
So the rate of heat rejection will be 347 GJ/hr