Answer:
C) The area of the sector TSV = 1.1 sq m.
Step-by-step explanation:
Here, the angle subtended by TSV at the center of the circle = 3 radians.
1 Radians = 57.2958°
So, 3 radians = 3 x 57.2958 = 171.887 °
⇒The angle of the sector TSV = 171.887 °
Now, the angle of any sector of a circle with angle Ф at the center
= [tex]\frac{\theta}{360} \times \pi \times (r^2)[/tex]
Here, r = 0.87 m
So, the area of the sector TSV = [tex]\frac{171.887}{360} \times \frac{22}{7} \times (0.87)^2 = 1.1358[/tex]
or, the area of the sector TSV = 1.13 sq m.
Now, rounding off the area to the nearest tenth ,we get:
The area of the sector TSV = 1.1 sq m.
