Explanation:
The given data is as follows.
[tex]P_{1}[/tex] = 1 atm, [tex]P_{2}[/tex] = 2 atm
[tex]V_{1}[/tex] = 250 ml, [tex]V_{2}[/tex] = 500 ml
Total volume = [tex]V_{1} + V_{2}[/tex] = 750 ml
Therefore, total pressure will be as follows.
[tex]P_{total} V_{total} = P_{1}V_{1} + P_{2}V_{2}[/tex]
[tex]P_{total} = \frac{P_{1}V_{1} + P_{2}V_{2}}{V_{total}}[/tex]
= [tex]\frac{1 atm \times 250 ml + 2 atm \times 500 ml}{750 ml}[/tex]
= 1.66 atm
Thus, we can conclude that total pressure of the given mixture is 1.66 atm.
