A 40 foot beam that weighs 125 pounds is supported at the two ends by walls. It also supports a 600 pound AC unit 5 feet from the right hand wall. Calculate the force the right hand wall (closest to the AC) must support.
A) 588 pounds
B) 138 pounds
C) 725 pounds
D) 608 pounds

Respuesta :

Answer:

A) 588 pounds

Explanation:

According to the given conditions, we assume the beam to be simply supported at the ends carrying a uniformly distributed load of 125 pounds per feet and a point load of 600 pounds acting at 5 feet from the right support.

Referring the schematic:

Moment about any point will be zero in equilibrium condition.

∴Take moment about point L

[tex]F_r\times 40=125\times 20+35\times 600[/tex]

[tex]F_r=587.5 lb[/tex]

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