Respuesta :
Answer:
[tex]y = 0.19 sin(5.23 t - 2.42x + \frac{\pi}{2})[/tex]
Explanation:
As we know that the wave equation is given as
[tex]y = A sin(\omega t - k x + \phi_0)[/tex]
now we have
[tex]A = 0.19 m[/tex]
[tex]\lambda = 2.6 m[/tex]
so we have
[tex]k = \frac{2\pi}{\lambda}[/tex]
[tex]k = \frac{2\pi}{2.6}[/tex]
[tex]k = 2.42 per m[/tex]
also we have
[tex]T = 1.2 s[/tex]
so we have
[tex]\omega = \frac{2\pi}{T}[/tex]
[tex]\omega = \frac{2\pi}{1.2}[/tex]
[tex]\omega = 5.23 rad/s[/tex]
now we know that at t = 0 and x = 0 wave is at y = 0.19 m
so we have
[tex]\phi_0 = \frac{\pi}{2}[/tex]
so we have
[tex]y = 0.19 sin(5.23 t - 2.42x + \frac{\pi}{2})[/tex]
