Respuesta :
Answer:
sensitivity = 0.5
specificity = 0.25
Predictive value = 0.5
Explanation:
Given data:
Total number of cases = 300
Total number of positively predicted = 200
Total number of actual positive = 100
NOte : 1/4th yield true positives
confusion matrix for given condition is given below
predicted: yes predicted: NO
actual: Yes TP = 50 FN = 50 = 100
actual: NO FP = 150 TN = 50
= 200 = 100
TP - true positive
FP - false positive
TN - true negative
FN - false negative
sensitivity [tex]=\frac{TP}{TP +FN} = \frac{50 }{50 + 50} = 0.5[/tex]
specificity [tex]= \frac{TN}{TN +FP} = \frac{50 }{50 + 150} = 0.25[/tex]
Predictive value [tex]= \frac{TP}{TP +FP} = \frac{50 }{50 + 50} = 0.5[/tex]
