Jada has p pennies and n nickels that add up to more than 40 cents. She had fewer than 20 coins altogether. Write a system of inequalities that represent how many pennies and nickels that jada could have.

Respuesta :

Answer:

5n+p>40

n+p<20

Step-by-step explanation:

Since pennies are worth 1 cent and nickels 5, using n as the number of nickels and p as the number of pennies, we can say that 5*n+1*p>40. Then, n+p is less than 20, so n+p<20. Our answer is then

5n+p>40

n+p<20

The currency called the dollar can be split into smaller forms called nickels, pennies, dimes, and quarters.

The system of inequalities that represents how many pennies and nickels that Jada could have is given as:

  • p + n < 20
  • 0.01p + 0.05n > 0.40

Let's represent the number of :

pennies = p

nickels = n

It is important to also note that:

1 penny = $0.01

1 nickel = $0.05

40 cents can also be written as: $0.40

Jada has p pennies and n nickels that add up to more than 40 cents.

The word more than means greater than and this can be represented by the inequality sign ">". Hence, our inequality equation is given as:

$0.01 x p + $0.05 x n > $0.40

0.01p + 0.05n > 0.40

She had fewer than 20 coins altogether.

The word fewer means less than and this can be represented by the inequality sign "<". Hence, our inequality equation is given as:

p + n < 20

Therefore, the system of inequalities that represents how many pennies and nickels that Jada could have is given as:

  • p + n < 20
  • 0.01p + 0.05n > 0.40

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https://brainly.com/question/19893558