Answer:
Explanation:
Expression for amplitude of forced damped oscillation is as follows
A = [tex]\frac{F_0}{\sqrt{m(\omega^2-\omega_0^2)^2+b^2\omega^2} }[/tex]
where
ω₀ =[tex]\sqrt{\frac{k}{m} }[/tex]
ω₀ = [tex]\sqrt{\frac{500000}{350} }[/tex]
=37.8
b = .125 ,
ω = 2.5
m = 350
A = [tex]\frac{100}{\sqrt{350(37.8^2-2.5^2)^2+.125^2\times2.5^2} }[/tex]
A = 3.75 mm . Ans