Answer:
(c) Total Number of moles = 3
Explanation:
To solve this question we have to follow the stoichiometry of the reaction and the fact that at equilibrium we have 1 mol of CH₃OH using the mnemonic helper RICE ( Reaction, Initial, Change, Equilibrium) as follows:
R CO(g) + 2 H₂ (g) ⇄ CH₃OH (g)
I (mol) 2 3 0
C (mol) -x x -2x + x
E (mol) 2-x 3-2x x
But we are told that at equilibrium x = mol CH₃OH = 1 , then at equilibrium we will have
E (mol) 2-(1) 3-2(1) 1
E (mol) 1 1 1
Therefore, the total number of moles of gas present in the container at equilibrium was 3