The question is missing the figure. So, the figure is attached below.
Answer:
237.375 ft³
Step-by-step explanation:
Given:
Side length of bigger cube is, [tex]S_1=8\ ft[/tex]
Side length of smaller cube is, [tex]S_2=6.5\ ft[/tex]
Now, volume of the bigger storage unit is given as:
[tex]V_1=S_1^3\\V_1=S_1\times S_1\times S_1\\V_1=8\times 8\times 8=512\ ft^3[/tex]
Volume of the smaller storage unit is given as:
[tex]V_2=S_2^3\\V_2=S_2\times S_2\times S_2\\V_2=6.5\times 6.5\times 6.5=274.625\ ft^3[/tex]
Now, difference in the volume of the two storage units is given as:
[tex]V_1-V_2=512-274.625=237.375\ ft^3[/tex]
Therefore, the difference in their volumes is 237.375 ft³.