Answer:
266.21 Pa.s
Explanation:
By Hagen–Poiseuille equation,
ΔP = 128 μ LQ/ πd2
Where;
Δp is the pressure difference between the two ends,
L is the length,
μ is the dynamic viscosity,
Q is the volumetric flow rate,
d = diameter
t = is the time
Δp = 2.35 KPa = 2.350Pa
L= 2.00 mm = 0.002m
μ = ??? (unknown)
Q = V × A
= (L/t) A
= Lπ[tex]d^{2}[/tex]/ 4t ( since A = [tex]d^{2}[/tex])
d= 5.00 μm = 5.00 × 10 -6
t = 1.45s
∴ 2350 = (128 μ L/ π[tex]d^{2}[/tex] ) × (L π[tex]d^{2}[/tex] / 4t)
Q(volumetric flow rate) = 32μ[tex]L^{2}[/tex] / [tex]d^{2}[/tex]t
From ΔP = 128 μ LQ/ π[tex]d^{2}[/tex]
μ = ΔP π[tex]d^{2}[/tex] / LQ
= (2350 [tex]d^{2}[/tex] / t) / 32L2
= [2350 × (5.00 × 10 -6 ) ( 1.45) / 32( 0.002)2]
= [(0.034075/ (32 × 0.000004)]
= 0.034075/ 0.000128
= 266.21 Pa.s
