Answer: a) 2.33V b) Ip = 0.0035A, Is = 0.179A
Explanation:
The relationship formula between the Voltage, Number of turns and current in a transformer is given as
Vp/Vs = Np/Ns = Is/Ip
Vp is voltage in the primary coil
Vs is voltage in the secondary coil
Ns is number of turns in the secondary coil
Np is number of turns in the primary coil
Is is current in the secondary coil
Ip is current in the primary coil
a) substituting the values in the formula
Vp/Vs = Np/Ns
120/Vs = 500/9.7
Vs = 120×9.7/500
Vs = 2.33V
b) since secondary now has a resistive load of 13 Ω, Using ohm's law to get current in the secondary
V=IR
Is = Vs/R
Is =2.33/13
Is = 0.179A
To get Ip, we will use the relationship Np/Ns = Is/Ip
500/9.7= 0.179/Ip
Ip = 9.7×0.179/500
Ip = 0.0035A
