Answer:
The length and width of the parking lot is 78 meters and 114 meters respectively.
Step-by-step explanation:
Given;
Perimeter of the parking lot = [tex]384\ m[/tex]
Solution,
Let the width of the parking lot be x.
Then, according to question length = (x-36).
The perimeter of a rectangle is sum of all the sides of rectangle. Which is given by an expression;
[tex]perimeter=2\times(length+width)[/tex]
Now substituting the values, we get;
[tex]384=2\times(x-36+x)\\\frac{384}{2}=(2x-36)\\192=2x-36\\192+36=2x\\2x=228\\x=\frac{228}{2}= 114[/tex]
Width = [tex]114\ m[/tex]
Length = [tex]x-36=114-36=78\ m[/tex]
Hence the length and width of the parking lot is 78 meters and 114 meters respectively.
