The beaker in the diagram below has a selectively permeable membrane separating two solutions. Assume that both water and salt can pass freely through the membrane. When equilibrium is reached, will the fluid levels be the same as they are now? Explain.​

The beaker in the diagram below has a selectively permeable membrane separating two solutions Assume that both water and salt can pass freely through the membra class=

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Answer

The movement of water molecules across a selectively permeable membrane is known as osmosis. A substance that moves by passive transport tends to move away from the area where it is more concentrated. Diffusion and osmosis both regard the dispersion of particles. By definition, water is the only substance that undergoes osmosis.

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When equilibrium is reached ; The Fluid level will be higher at solution A ( Side A )

Given that the solutions are separated by a selectively permeable membrane which allows only water and salt through it. and the solution in side A is a concentrated salt solution ( higher percentage of salt ( solute ) ) while the solution on side B is a dilute solution with a lesser percentage of salt and starch.

The salt and water from side B will move through the membrane into side A leading to the decrease in the fluid levels of Side B. This is because during osmosis the movement of water molecule is from a region of higher water concentration to a region of lower water concentration.

Hence we can conclude that When equilibrium is reached The Fluid level will be higher at solution A ( Side A ).

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