The angle of incidence in glass is [tex]34.7^{\circ}[/tex]
Explanation:
We can solve this problem by applying Snell's law of refraction, which states that:
[tex]n_1 sin \theta_1 = n_2 sin \theta_2[/tex]
where
[tex]n_1, n_2[/tex] are the index of refraction of the first and second medium, respectively
[tex]\theta_1, \theta_2[/tex] are the angle of incidence and refraction, respectively
In this problem we have:
[tex]n_1 = 1.52[/tex] is the index of refraction of the first medium (glass)
[tex]n_2 = 1.00[/tex] is the index of refraction of the second medium (air)
[tex]\theta_2 =60^{\circ}[/tex] is the angle of refraction in glass
Solving for [tex]\theta_i[/tex], we find the angle of incidence:
[tex]\theta_1 = sin^{-1} (\frac{n_2 sin \theta_2}{n_1})=\sin^{-1}(\frac{(1.00)(sin 60^{\circ})}{1.52})=34.7^{\circ}[/tex]
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