Answer: 0.088 moles
Explanation:
Parameters given:
Mass of AgNO3 = 15.0g
To know the number of moles, given such parameter, we need to find and use the molecuar weight formular. The molecuar weight is mass per mole
Molecular weight = mass / mole
Molecular weight of AgNO3
Ag + N + 03
107.8682 + 14.0067 + 15.9994(3)
(Note, that the weight of each compounds are standards)
= 169.8731g/mole
Using our molecular weight formular
Moles of AgNO3 in 15.0g
Let Number of Moles be represented as Y
169.8731g/mole = 15.0g / Y
Therefore,
Y = 169.8731 / 15.0g
Y = 0.088 moles
No of Moles of AgNo3 in 15.0g = 0.088moles
