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A compound microscope is made with an objective lens (f0 = 0.900 cm) and an eyepiece (fe = 1.10 cm). The lenses are separated by a distance of 10.0 cm. What is the angular magnification? (Assume the near point is 25.0 cm.)

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Answer:

-252.52

Explanation:

L = Distance between lenses = 10 cm

D = Near point = 25 cm

[tex]f_o[/tex] = Focal length of objective = 0.9 cm

[tex]f_e[/tex] = Focal length of eyepiece = 1.1 cm

Magnification of a compound microscope is given by

[tex]m=-\frac{L}{f_o}\frac{D}{f_e}\\\Rightarrow m=-\frac{10}{0.9}\times \frac{25}{1.1}\\\Rightarrow m=-252.52[/tex]

The angular magnification of the compound microscope is -252.52

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