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The synthesis of methanol from carbon monoxide and hydrogen gas is described by the following chemical equation:

CO(g)+2H2(g)?CH3OH(g)

The equilibrium constant for this reaction at 25 ?Cis Kc=2.3×104. In this tutorial, you will use the equilibrium-constant expression to find the concentration of methanol at equilibrium, given the concentration of the reactants.

The equilibrium-constant expression is a mathematical equation that can be rearranged to solve for any of the variables in it. Rearrange the equilibrium-constant expression to solve for [CH3OH].

Kc[CO][H2]^2

Suppose that the molar concentrations for CO and H2 at equilibrium are [CO] = 0.02 M and [H2] = 0.06 M.

Use the formula you found in Part B to calculate the concentration of CH3OH.

Express your answer to one decimal place and include the appropriate units.

Respuesta :

Answer:

[CH3OH(g)] = 1.7 M

Explanation:

  • CO(g) + 2H2(g) ↔ CH3OH(g)

∴ Kc(25°C) = 2.3 E4 = [CH3OH(g)] / [CO(g)]×[H2(g)]²

⇒ [CH3OH(g)] = Kc.[CO(g)][H2(g)]²

∴ [CO(g)] = 0.02 M

∴ [H2(g)] = 0.06 M

⇒ [CH3OH(g)] = (2.3 E4)(0.02)(0.06)²

⇒ [CH3OH(g)] = 1.7 M

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