Water is boiling in an aluminum pan placed on an electrical element on a stovetop. The pan has a bottom that is 0.800 cm thick and 14.0 cm in diameter. Aluminum thermal conductivity is 220 W/(m oC). In every second, 1.2 g boiling water evaporates. The latent heat of vaporization for water is 2.26 × 106 J/kg. (a) How much heat is transfered to the boiling water in one second?

Respuesta :

Explanation:

The given data is as follows.

    Thickness = 0.8 cm = [tex]0.8 \times 10^{-3} m[/tex]    (As 1 m = 1000 cm)

    Diameter = 14.0 cm,   Conductivity = [tex]220 W/(m^{o}C)[/tex]

    mass = 1.2 g,       L = [tex]2.26 \times 10^{6} J/kg[/tex]

Now, we will calculate the heat of vaporization for water as follows.

               Q = mL

           Q = [tex]0.8 \times 10^{-3} \times 2.26 \times 10^{6}[/tex]

           Q = 1808 J

So, rate of heat transfer in 1 sec  will be as follows.

       [tex]\frac{Q}{t}[/tex] = 1808 J/s

Thus, we can conclude that 1808 J/s heat is transfered to the boiling water in one second.