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Two electrons 1 and 2 move along antiparallel paths separated by a distance of 10 nm, traveling at speeds 4.5 x 10^7 m/s and 8.0 x 10^6 m/s.
Part A) What is the magnitude of the magnetic force exerted by electron 2 on electron 1? Express your answer with the appropriate units.

Respuesta :

Answer:

The magnetic force on electron 1 by electron 2=[tex]9.22\times 10^{-15} N[/tex]

Explanation:

We are given that

Distance between two electrons=10 nm

Speed of electron 1=[tex]4.5\times 10^7[/tex] m/s

Speed of electron 2=[tex]8.0\times 10^6[/tex] m/s

We have to find the magnitude of the magnetic force exerted  by electron 2 on electron 1.

Magnetic force on electron 1 by electron 2

[tex]F=\frac{\mu_0e^2v_1v_2}{4\pi r^2}[/tex]

[tex]\frac{\mu_0}{4\pi}=10^{-7}[/tex]

[tex]e=1.6\times 10^{-19} C[/tex]

[tex]v_1=4.5\times 10^7 m/s[/tex]

[tex]v_2=8.0\times 10^6 m/s[/tex]

[tex]r=10nm=10\times 10^{-9}m[/tex] [tex](1nm=10^{-9} m[/tex])

Substitute the values in the given formula

The magnetic force on electron 1 by electron 2=[tex]\frac{10^{-7}\times (1.6\times 10^{-19})^2\times 4.5\times 10^7\times 8\times 10^6}{(10\times 10^{-9})^2}[/tex]

The magnetic force on electron 1 by electron 2=[tex]9.22\times 10^{-15} N[/tex]

Hence, the magnetic force on electron 1 by electron 2=[tex]9.22\times 10^{-15} N[/tex]

The magnitude of the magnetic force exerted by electron 2 on electron 1 is [tex]9.22\times10^{-15}[/tex] N.

What is magnetic force?

Magnetic force is the force of attraction of repulsion between two poles of the two magnets. The magnetic force is also appears between two electrically charged bodies.

The magnetic force can be given as,

[tex]F=\dfrac{\mu_oq_1q_2(v_1v_2)}{4\pi r^2}[/tex]

Here, ([tex]\mu_o[/tex]) is the magnetic constant, (q) is the charge on the body, (v) is the speed of the body and (r) is the distance between them.

The distance between the electrons 1 and 2 is 10 nm. As the speed of the electron 1 is [tex]4.5 \times10^7[/tex] m/s and the speed of the electron 2 is [tex]8.0 \times10^6[/tex] m/s.

Thus, put the values in the above formula as,

[tex]F=\dfrac{4\pi \times10^{-7}\times1.6\times10^{-19}\times1.6\times10^{-19}\times4.5\times10^{7}(8.0\times10^6)}{4\pi (10^{-9})^2}[/tex]

[tex]F=9.22\times10^{-15}\rm N[/tex]

Thus the magnitude of the magnetic force exerted by electron 2 on electron 1 is [tex]9.22\times10^{-15}[/tex] N.

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