Answer:20.03 m/s
Explanation:
Given
[tex]L_r=1:7[/tex]
velocity of Prototype [tex]v_p=53 m/s[/tex]
Taking Froude number same for both flow as it is a dimensionless number for different flow regimes in open Flow
[tex](\frac{v_m}{\sqrt{L_mg}})=(\frac{v_p}{\sqrt{L_pg}})[/tex]
[tex]v_m=v_p\times \sqrt{\frac{L_m}{L_p}}[/tex]
[tex]v_m=53\times \frac{1}{\sqrt{7}}[/tex]
[tex]v_m=20.03 m/s[/tex]