Answer:
t=12.6 cm
Explanation:
Given that
Q= 150 W
T₁ = −1.00ºC
T₂ = 37.0ºC
A= 2 m²
Lets take thermal conductivity of blubber
K= 0.25 W/(m.K)
Lets take thickness = t
We know that heat transfer due to conduction given as
[tex]Q=KA\dfrac{(T_2-T_1)}{t}[/tex]
[tex]t=KA\dfrac{(T_2-T_1)}{Q}[/tex]
[tex]t=0.25\times 2\times \dfrac{(37 + 1)}{150}[/tex]
t=0.126 m
t= 12.6 cm
Therefore thickness of the blubber is 12.6 m.