Answer:
A=0.0267 m
Explanation:
Given that
m= 33 g= 0.033 kg
Frequency ,f= 3.05 Hz
We know that
ω = 2 π f
ω = 2 x 3.05 π
ω = 6.1 π s⁻¹
ω² m = K
K=Spring constant
(19.16)² x 0.033 = K
K = 12.11 N/m
The maximum amplitude A
K A = m g
12.11 x A= 0.033 x 9.81
A=0.0267 m