Fnet = ma = m*0.23g = mgsinΘ - Ff
where Ff is the friction force upslope.
net torque τ = Ff * r,
but also τ = I*α =(2/3)mr² * a/r = 2mra/3 = 2mr(0.23g)/3 = 0.46mrg/3
Then Ff * r = 0.46mrg / 3
Ff = 0.46mg/3 → put this into net force equation:
m*0.23g = mgsinΘ - 0.46mg/3 → mg cancels; multiply through by 3
0.69 = 3sinΘ - 0.46
3sinΘ = 1.15
sinΘ = 1.15/3
Θ = arctan(1.15/3) = 22.54 º
