Answer:
The deformation in the pole due to force is 0.70 mm.
Explanation:
Given that,
Height = 20.0 m
Diameter = 4.00 cm
Force = 1100 N
We need to calculate the area
Using formula of area
[tex]A=\pi\times r^2[/tex]
[tex]A=\pi\times(2.00\times10^{-2})^2[/tex]
[tex]A=0.00125\ m^2[/tex]
[tex]A=1.25\times10^{-3}\ m^2[/tex]
We need to calculate the deformation
Using formula of deformation
[tex]\Delta x=\dfrac{1}{s}(\dfrac{F}{A}\times L)[/tex]
Where, s = shear modulus
F = force
l = length
A = area
Put the value into the formula
[tex]\Delta x=\dfrac{1}{2.5\times10^{10}}\times(\dfrac{1100}{1.25\times10^{-3}}\times 20.0)[/tex]
[tex]\Delta x=0.000704\ m[/tex]
[tex]\Delta x=7.04\times10^{-4}\ m[/tex]
[tex]\DElta x=0.70\ mm[/tex]
Hence, The deformation in the pole due to force is 0.70 mm.
