Answer:[tex]5.67\times 10^{3} m/s[/tex]
Explanation:
Given
mass of satellite [tex]m=155 kg[/tex]
Satellite is orbiting 5995 km above Earth surface
mass of Earth [tex]M=5.97\times 10^{24} kg[/tex]
Radius of Earth [tex]R=6370 km[/tex]
here [tex]r=R+5995=6370+5995=12,365 km[/tex]
Gravitational Force will Provide the centripetal Force
[tex]\frac{GMm}{r^2}=\frac{mv^2}{r}[/tex]
[tex]v=\sqrt{\frac{GM}{r}}[/tex]
[tex]v=\sqrt{\frac{6.67\times 10^{-11}\times 5.97\times 10^{24}}{12365\times 10^{3}}}[/tex]
[tex]v=\sqrt{32.203\times 10^6}[/tex]
[tex]v=5.67\times 10^3m/s=5674.7 km/s[/tex]
