Answer:
Step-by-step explanation:
[tex]f(x)=36x^5-44x^4-28x^3\\\\g(x)=4x^2\\\\\dfrac{f(x)}{g(x)}=\dfrac{36x^5-44x^4-28x^3}{4x^2}\\\\\dfrac{f(x)}{g(x)}=\dfrac{(4x^2)(9x^3)-(4x^2)(11x^2)-(4x^2)(7x)}{4x^2}\\\\\dfrac{f(x)}{g(x)}=\dfrac{(4x^2)(9x^3-11x^2-7x)}{4x^2}\qquad\text{cancel}\ 4x^2\\\\\dfrac{f(x)}{g(x)}=9x^3-11x^2-7x[/tex]
Answer:option C is the correct answer
Step-by-step explanation:
f(x) = 36x^5 − 44x^4 − 28x^3
g(x) = 4x^2
We want to determine f(x)/g(x). It becomes
(36x^5 − 44x^4 − 28x^3) /(4x^2)
Looking at the numerator, each term in the numerator can divide the term in the denominator without remainder. it means that the term in the denominator is a common factor of the numerator and thus, 4x^2 can be factorized out of the numerator. It becomes
4x^2(9x^3 − 11x^2 − 7x) /(4x^2)
4x^2 in the numerator cancels out 4x^2 in the denominator. It becomes
9x^3 − 11x^2 − 7x
