Answer:
B and D
Step-by-step explanation:
[tex]\dfrac{a}{b}\times c=\dfrac{a\times c}{b}\\\\a\times\dfrac{b}{c}=\dfrac{a\times b}{c}\\\\\dfrac{a}{b}:c=\dfrac{a}{b}\times\dfrac{1}{c}=\dfrac{a}{b\times c}\\\\a:\dfrac{b}{c}=a\times\dfrac{c}{b}=\dfrac{a\times c}{b}\\\\\dfrac{a}{b}\times\dfrac{c}{d}=\dfrac{a\times c}{b\times d}\\\\\dfrac{a}{b}:\dfrac{c}{d}=\dfrac{a}{b}\times\dfrac{d}{c}=\dfrac{a\times d}{b\times c}\\\\============================[/tex]
[tex]\bold{A}\\\\\dfrac{1}{3}\times2=\dfrac{1\times2}{3}=\dfrac{2}{3}<1\\\\\bold{B}\\\\2:\dfrac{1}{3}=2\times\dfrac{3}{1}=2\times3=6>1\\\\\bold{C}\\\\\dfrac{1}{4}\times\dfrac{2}{3}=\dfrac{1\times2}{4\times3}=\dfrac{2}{12}<1\\\\\bold{D}\\\\\dfrac{3}{4}:\dfrac{2}{3}=\dfrac{3}{4}\times\dfrac{3}{2}=\dfrac{3\times3}{4\times2}=\dfrac{9}{8}=1\dfrac{1}{8}>1\\\\\bold{E}\\\\\dfrac{2}{3}\times\dfrac{3}{4}=\dfrac{2\times3}{3\times4}=\dfrac{6}{12}<1\\\\\bold{F}\\\\\dfrac{2}{3}:\dfrac{3}{4}=\dfrac{2}{3}\times\dfrac{4}{3}=\dfrac{2\times4}{3\times3}=\dfrac{8}{9}<1[/tex]
