Respuesta :
Answer:
six raised to the one twelfth power
Step-by-step explanation:
The cubed root of 6/the fourth root of 6 equals (6^1/3)/(6^1/4)
6^((1/3)-(1/4))
6^((4-3)/12)
6^1/12
The simplified form of the expression is six raised to the one twelfth power
Given the expression
- [tex]\dfrac{\sqrt[3]{6} }{\sqrt[4]{6} }[/tex]
According to indices, this expression can also be written as:
- [tex]\dfrac{(6)^{1/3}}{6^{1/4}}[/tex]
Using the law of indices;
[tex]\dfrac{a^m}{a^n} = a^{m-n}[/tex]
Applying this expression will give:
[tex]=\dfrac{6^{1/3}}{6^{1/4}} \\= 6^{1/3-1/4}\\=6^{4-3/12}\\=6^{1/12}[/tex]
Hence the simplified form of the expression is six raised to the one twelfth power
Learn more on indices here: https://brainly.com/question/8952483