Respuesta :
Answer:
The allowed current in the cable is 1.15 A.
Explanation:
Given that,
Distance = 1.00 m
Suppose the magnetic field is [tex]2.3\times10^{-5}\ T[/tex] and if the experiment is to be accurate to 1.0 %
We need to calculate the current
Using formula of magnetic field
[tex]B=\dfrac{\mu_{0}I}{2\pi r}[/tex]
[tex]I=\dfrac{B\times2\pi r}{\mu_{0}}[/tex]
Put the value into the formula
[tex]I=\dfrac{2.3\times10^{-5}\times2\times\pi\times1.00}{4\pi\times10^{-7}}[/tex]
[tex]I=115\ A[/tex]
If the experiment is to be accurate to 1.0%
Then,
We need to calculate the allowed current in the cable
[tex]I'=(1.0%)\times I[/tex]
[tex]I'=\dfrac{1.0}{100}\times115[/tex]
[tex]I'=1.15\ A[/tex]
Hence, The allowed current in the cable is 1.15 A.
