Answer:
[tex]10|y|[/tex]
Step-by-step explanation:
We have been given that the vertices of a triangle are A (5, 0), B (x, y) and C (25, 0). We are asked to find the area of the given triangle.
We will use area formula for triangle with vertices A, B and C as given below:
[tex]|\frac{A_x(B_y-C_y)+B_x(C_y-A_y)+C_x(A_y-B_y)}{2}|[/tex]
Upon substituting the given coordinates of points A, B and C in above formula, we will get:
[tex]|\frac{5(y-0)+x(0-0)+25(0-y)}{2}|[/tex]
[tex]|\frac{5(y)+x(0)+25(-y)}{2}|[/tex]
[tex]|\frac{5y+0-25y}{2}|[/tex]
[tex]|\frac{-20y}{2}|[/tex]
[tex]|-10y|[/tex]
[tex]10|y|[/tex]
Therefore, the area of the given triangle would be [tex]10|y|[/tex].
