The actual volume of the liquid is [tex]50 cm^2[/tex]
Explanation:
When doing a measurement, there are two types of errors that we can define:
- Absolute error: it is the absolute value of the error on the measurement. In this case, it is [tex]E_a = 0.6 cm^3[/tex]
- Relative error: it is the error expressed as a fraction of the value of the measurement. Mathematically, [tex]E_r = \frac{E_a}{V}\cdot 100[/tex], where [tex]E_a[/tex] is the absolute error, V is the measurement (the volume, in this case). In this problem, [tex]E_r = 1.2\%[/tex]
In this problem we have:
[tex]E_a=0.6 cm^2[/tex] (absolute error)
[tex]E_r = 1.2\%[/tex] (relative error)
Using the formula for the relative error, we can find the actual value of the volume of the liquid:
[tex]V=\frac{E_a}{E_r}\cdot 100 = \frac{0.6}{1.2}\cdot 100 =50 cm^3[/tex]
Learn more about errors:
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