The second hand of a clock is 8 cm long what is the distance of the tip of the second hand travel in 10 minutes
Answer:
The distance travelled by tip of second hand in 10 minutes is 502.4 cm
Solution:
Length of second hand = 8 cm long
In one revolution it travels a circumference of a circle of which radius is 8 cm
The circumference of circle = [tex]2 \pi r[/tex]
[tex]c = 2 \times \pi \times 8 = 16\pi[/tex]
We are aksed to find the distance of the tip of the second hand travel in 10 minutes
Second hand complete 1 revolution in 1 minute.
Therefore, in 10 minutes it revolves 10 revolution,
In 1 revolution tip of second covers = 16π
Hence distance travelled is given as:
[tex]\rightarrow 16 \pi \times10 = 160 \pi[/tex]
We know that π is a constant equals to 3.14
[tex]\rightarrow 160 \pi = 160 \times 3.14 = 502.4[/tex]
Thus the distance travelled by tip of second hand in 10 minutes is 502.4 cm
