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Look at the rectangle and the square:

Anna says that the length of diagonal SQ is two times the length of diagonal OM.

Is Anna correct? Justify your answer and show all your work. Your work should state the theorem you used to find the lengths of the diagonals.

Look at the rectangle and the square Anna says that the length of diagonal SQ is two times the length of diagonal OM Is Anna correct Justify your answer and sho class=

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frika

Answer:

Anna is incorrect.

Step-by-step explanation:

Find lengths of diagonals SQ and OM.

1. Consider right triangle SQR. By the Pythagorean theorem,[tex]SQ^2=SR^2+RQ^2\\ \\SQ^2=14^2+7^2\\ \\SQ^2=196+49\\ \\SQ^2=245\\ \\SQ=\sqrt{245}=7\sqrt{5}\ units[/tex]

2. Consider right triangle OML. By the Pythagorean theorem,

[tex]OM^2=OL^2+LM^2\\ \\OM^2=7^2+7^2\ [\text{In square LMNO, side } OL \text{has the same length as side }LM]\\ \\OM^2=49+49\\ \\OM^2=98\\ \\OM=\sqrt{98}=7\sqrt{2}\ units[/tex]

Since [tex]7\sqrt{5}\neq 2\cdot 7\sqrt{2}=7\sqrt{8},[/tex] diagonal SQ is not two times diagonal OM. Thus, Anna is incorect.

Answer:

Anna is not correct

Step-by-step explanation:

 Part A: No, anna is not correct because first the rectangle (PQRS) its says that the length of (SR) is 14 inches and if cut in half at the diagonal a rectangle or a square would have 2 triangles so if A2 + B2 = C2 then if C = the length of the diagonal and A would = 14 in ( the length of the rectangle) and then B would = 7 inches which is the width of the rectangle. It concludes that 14 to the power of 2 + 7 to the power of 2 = 245 which its square root is 15.65 ( if rounded to the hundredth place) 

Part B: Next, is the square (LMNO) if its length and width are both 7 inches then A2 = 7 to the power of 2 and also B2 will also = 7to the power of 2 and C2 will = will be the length of the diagonal.So, all of that 7 to the power of 2 + 7 to the power of 2 = 98 and its square root is 9.89 ( if rounded to the hundredth place) so lets just say 9.9.

Then you can see that 9.9 times 2 does not equal 15.65 so Anna was wrong.  

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