Function 2 has greater rate of change
Step-by-step explanation:
In order to find the rate of change we have to covert the given linear functions in slope-intercept form
Function 1:
[tex]-2x+5y = 10[/tex]
Adding 2x on both sides
[tex]-2x+5y+2x = 2x+10\\5y = 2x+10[/tex]
Dividing both sides by 5
[tex]\frac{5y}{5} = \frac{2x+10}{5}\\y = \frac{2}{5}x +\frac{10}{5}\\y = \frac{2}{5}x+2[/tex]
Let m1 be rate of change of function 1:
[tex]m_1 = \frac{2}{5}[/tex]
Function 2:
[tex]-6x+3y = 18[/tex]
Adding 6x on both sides
[tex]-6x+3y+6x = 6x+18\\3y = 6x+18[/tex]
Dividing both sides by 3
[tex]\frac{3y}{3} = \frac{6x+18}{3}\\y = \frac{6x}{3} + \frac{18}{3}\\y= 2x+6[/tex]
Let m2 be the slope of function 2
[tex]m_2 = 2[/tex]
As we can see that
[tex]m_2>m_1[/tex]
Function 2 has greater rate of change
Keywords: Linear functions, slope
Learn more about functions at:
- brainly.com/question/10699220
- brainly.com/question/10703930
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