Answer:
[tex]8.71[/tex] %
Explanation:
We will find solution to this question by using normal distribution method.
We are required to find
[tex]P(X\geq 110)[/tex]
We will find the z-score
[tex]z = \frac{x-\alpha }{\beta*\sqrt{n} }[/tex]
Where
[tex]\alpha[/tex] is the means and [tex]\beta[/tex] is the standard deviation and n represents the number of sample
Substituting the given values, we get -
[tex]z = \frac{110-100}{15\sqrt{9} } \\z = 0.223[/tex]
Thus, area to the right side of [tex]0.67[/tex] in a normal distribution curve is will represent [tex]P (Z>0.223)[/tex]
[tex]P(X\geq 110)[/tex] [tex]=[/tex][tex]P (Z>0.223)[/tex]
[tex]= 0.0871[/tex]
