The mouse's average speed between t=1.0s and t=4.0s is [tex]0.6m/s[/tex]
The mouse's position as a function of time is given by ,
[tex]x(t)=pt^{2}+qt[/tex]
Substitute p = 0.36 and q = -1.20 in above relation.
[tex]x(t)=0.36t^{2}-1.2t[/tex]
[tex]x(1)=0.36-1.2=-0.84m\\\\x(4)=5.76-4.8=0.96m[/tex]
the mouse's average speed between t=1.0s and t=4.0s is,
[tex]v=\frac{x(4)-x(1)}{4-1} =\frac{0.96+0.84}{3}=0.6m/s[/tex]
Learn more:
https://brainly.com/question/11753352