Answer:
Pressure of the gas is greater than the vapor pressure, therefore all the solid will not sublime.
Explanation:
To solve this problem we use ideal gas equation.
PV =nRT
If Presure of the gas (P) is greater than vapor pressure (56.5 atm), all the solid will not sublime. But If P < 56.5 atm, all of it will sublime.
where;
P is pressure of the gas in atm
V is volume of gas in Litre
T is absolute temperature of the gas in Kelvin
n is number of gas moles
R is ideal gas constant or Boltzmann constant = 0.082057 L atm K⁻¹ mol⁻¹
Given T = 20 °C = 273 + 20 = 293K
Volume = 0.25L
n = Reacting mas (m)/Molar mass(M)
Molar mass of CO₂ = 12 + (16X2) = 12+32 = 44g/mol
Reacting mass = 10g
n = m/M ⇒ 10/44
n = 0.2273
PV =nRT ⇒ P = nRT/V
P = (0.2273X0.082057 X293)/0.25
P = 21.8596 atm
Therefore, since Pressure of the gas is greater than the vapor pressure, all the solid will not sublime.
