Answer:
[tex]20838.6[/tex]
Explanation:
We are first required to calculate the amount of kilo calories in one lb or one pound of fat.
One pound is equal to [tex]454[/tex] grams.
One gram of fat contains [tex]9[/tex] kilo calories.
Thus, the total kilo calories in one pound of body fat is equal to
[tex]454 * 9\\4086[/tex]
Total kilo calories in six pound of body fat is equal to
[tex]4086 * 6\\24516[/tex]
Now, excluding the weight of water, we can say that one grams of fat is actually equal to
[tex]1 - 0.15\\0.85[/tex]
grams.
Thus, the total kilo calories to be spend after removing the water from the fat is equal to
[tex]24516 * 0.85\\20838.6[/tex]
If you want to lose 6 lb of body fat, the amount of kilocalories you need to expend is 20,838.6 kcal.
Given the following data:
Body fat = 6 lb
Percentage of water = 15% = 0.15
Conversion:
1 lb = 454 grams
6 lb = [tex]454\times 6=2724\;grams[/tex]
To determine the amount of kilocalories you need to expend:
Scientifically, nine (9) kilocalories is required to burn one (1) gram of fat.
By direct proportion:
1 gram of fat = 9 kcal.
2724 = X kcal.
Cross-multiplying, we have:
[tex]X=2724\times 9\\\\X=24,516\;kcal.[/tex]
Since we were told that six (6) pounds of body fat is equivalent to water, then the remaining percent composition would be equal to fat.
[tex]Fat = 1-0.15\\\\Fat = 0.85[/tex]
Therefore, 85 percent represents the body fat.
For total kilocalories:
[tex]Total \;kilocalories = 0.85 \times 24516[/tex]
Total kilocalories = 20,838.6 kcal.
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