Answer:
Part 1) The inverse function is [tex]f^{-1}(x) =\frac{2x-3}{4}[/tex]
Part 2) 25.75 weeks
Step-by-step explanation:
Let
x ---->the number of weeks in the course
f(x) ---> the number of assignments he has completed
we have
[tex]f(x)=\frac{4x-3}{2}[/tex]
Part 1) Find the inverse
Let
y=f(x)
[tex]y=\frac{4x-3}{2}[/tex]
Exchange the variables (x for y and y for x)
[tex]x=\frac{4y-3}{2}[/tex]
Isolate the variable y
[tex]2x=4y-3\\4y=2x+3\\\\y=\frac{2x+3}{4}[/tex]
Let
[tex]f^{-1}(x) =y[/tex]
so
[tex]f^{-1}(x) =\frac{2x+3}{4}[/tex]
Part 2) we have
[tex]f^{-1}(x) =\frac{2x+3}{4}[/tex]
where
[tex]f^{-1}(x)[/tex] ---->the number of weeks in the course
x ---> the number of assignments he has completed
For x=50
substitute in the inverse function
[tex]f^{-1}(x) =\frac{2(50)+3}{4}=25.75\ weeks[/tex]
Note: Juliana don't need to use the inverse function. you can just use the function you have where f(x)=50 assignments and solve for x to get the amount of weeks.
so
[tex]50=\frac{4x-3}{2}\\\\100=4x-3\\4x=103\\x=25.75\ weeks[/tex]