Answer:
V = 44.83 L
Explanation:
Given data:
Mass of fluorine = 76 g
Temperature = 0°C
Pressure = 101.3 Kpa
Volume of fluorine = ?
Solution:
Temperature = 0°C (0°C + 273 = 273 K)
Pressure = 101.3 Kpa ( 101.3 / 101 = 1 atm)
First of all we will calculate the number of moles.
Number of moles of F = Mass/ molar mass
Number of moles = 76 g/ 38 g/mol
Number of moles = 2 mol
Volume of fluorine:
Formula
PV = nRT
V = nRT/ P
V = 2 mol × 0.0821 atm. L/ mol. k × 273 k / 1 atm
V = 44.83 L. atm / 1 atm
V = 44.83 L
