The first three terms of a sequence are given. Round to the nearest thousandth (if necessary).
3, 9,15,...
Find the 36th term.
​ I need help!

Respuesta :

Answer: 213

Step-by-step explanation:

Given :

[tex]3 , 9 , 15 , ...[/tex]

The difference between the first term and the second term is 6 and the difference between the third term and the second term is 6 , this means that the sequence is an Arithmetic sequence.

The formula for calculating the nth term of an arithmetic sequence is given as :

[tex]t_{n}[/tex] = [tex]a + (n-1)d[/tex]

where :

a = first term

n = number of terms

d = common difference

Therefore , the 36th term will be :

[tex]t_{36}[/tex] = [tex]3 + (36-1)(6)[/tex]

[tex]t_{36}[/tex] = [tex]3 + 35(6)[/tex]

[tex]t_{36}[/tex] = [tex]3 + 210[/tex]

[tex]t_{36}[/tex] = [tex]213[/tex]

Therefore : the 36th term = 213